Java.lang.illegalargumentexception: Software Rendering Doesn't Support Hardware Bitmaps

How to solve an IllegalArgumentException in Coffee?

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An IllegalArgumentExceptionis thrown in order to betoken that a method has been passed an illegal argument. This exception extends the RuntimeExceptioncourse and thus, belongs to those exceptions that can be thrown during the operation of the Java Virtual Machine (JVM). It is an unchecked exception and thus, it does non need to be declared in a method's or a constructor's throws clause.

Reasons for java.lang.IllegalArgumentException

• When Arguments out of range. For instance, the pct should lie betwixt 1 to 100. If the user entered 101 then an IllegalArugmentExcpetionwill be thrown.
• When statement format is invalid. For example, if our method requires appointment format similar YYYY/MM/DD but if the user is passing YYYY-MM-DD. And so our method can't sympathise then IllegalArugmentExcpetionwill be thrown.
• When a method needs non-empty string as a parameter but the naught cord is passed.

Example1

public class Pupil {    int m;    public void setMarks(int marks) {       if(marks < 0 || marks > 100)          throw new IllegalArgumentException(Integer.toString(marks));       else          m = marks;    }    public static void master(String[] args) {       Student s1 = new Student();       s1.setMarks(45);       System.out.println(s1.m);       Student s2 = new Educatee();       s2.setMarks(101);       System.out.println(s2.grand);    } }

Output

45 Exception in thread "main" coffee.lang.IllegalArgumentException: 101 at Student.setMarks(Student.coffee:five) at Student.principal(Student.coffee:15)

Steps to solve IllegalArgumentException

• When an IllegalArgumentExceptionis thrown, we must check the telephone call stack in Java's stack trace and locate the method that produced the incorrect statement.
• The IllegalArgumentExceptionis very useful and can be used to avert situations where the application's lawmaking would take to deal with unchecked input data.
• The main use of this IllegalArgumentExceptionis for validating the inputs coming from other users.
• If nosotros want to take hold of the IllegalArgumentExceptionthen we can use try-catch blocks. By doing similar this we can handle some situations. Suppose in catch block if we put code to give another chance to the user to input once again instead of stopping the execution particularly in case of looping.

Example2

import coffee.util.Scanner; public class Student {     public static void main(String[] args) {         Cord cont = "y";         run(cont);     }     static void run(String cont) {         Scanner browse = new Scanner(Arrangement.in);         while( cont.equalsIgnoreCase("y")) {            try {                Arrangement.out.println("Enter an integer: ");                int marks = scan.nextInt();                if (marks < 0 || marks > 100)                   throw new IllegalArgumentException("value must be non-negative and beneath 100");                System.out.println( marks);             }             catch(IllegalArgumentException i) {                System.out.println("out of range encouneterd. Want to continue");                cont = scan.next();                  if(cont.equalsIgnoreCase("Y"))                    run(cont);                }           }      } }

Output

Enter an integer: 1 1 Enter an integer: 100 100 Enter an integer: 150 out of range encouneterd. Want to continue y Enter an integer:

Published on 04-Jun-2019 12:45:08

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